Cook's New Electrogravity
Theory
The NET 10 - Mach-Cook Parallel
Note: the page has directed some visitors
from the Mach-Cook
Parallel introduction to here. For
those of you just joining, welcome to the
New Electrogravity Theory (the NET).
We're in mid-discussion now, so please try
not to interfere with the others who are way
advanced by now and don't need distractions
at this point from those just joining. Ahem...
Okay, that last page involved some heavy
equations. And if you're like most people
and not terribly a lover of math, you probably
didn't grasp, nor care for, much of that last
page. Fortunately we will start this page
off extraordinarily easy, as easy as one plus
one. However, to do so, we are cheating a
bit, as we will leave the proof of one important
finding of Mr. Cook's for a later page or
a later date. The reason for this is because
it involves tetration techniques and
homeomorphic factors that are way,
way beyond anything anyone is going to want
to read here. In fact, Cook even needed
to submit the equations to an expert on tetration
in order to prove it, which this other kind
gentleman effortlessly did.
Again, we will keep it as simple as possible
here in order to maintain readership only.
The tetration proof will be provided later
and outside the NET. Just so one understands
that the final equation on this page is not
ad hoc in the least; it is proven mathematically.
Let's explore some torus geometry. Like a
donut, a torus has an outer radius and an
inner radius. The electron travels around
the proton in such a formation. The NET has
their values as this, where the Inner and
Outer radii are simply separated by the width
of the electron.

Where B_r is the Bohr radius
of Hydrogen from (5)
and e_r is the electron radius
from (2).
At n = 1
O_r = -5.292053... x 10^-11 m
At n = 2
O_r = -2.116737... x 10^-10 m
At n = 3
O_r = -4.762623... x 10^-10 m

Where B_r is the Bohr radius
of Hydrogen from (5)
and e_r is the electron radius
from (2).
At n = 1
I_r = -5.291490... x 10^-11 m
At n = 2
I_r = -2.116680... x 10^-10 m
At n = 3
I_r = -4.762566... x 10^-10 m
With the Inner and outer radii known, the
surface area of Hydrogen can be calculated.

Where O_r is the outer radius
of Hydrogen from (101) above, I_r is
the inner radius from (102) above,
pi is the Irrational number equal to
3.14159..., lambda_eo is the Electron
Orbit Wavelength from (11),
lambda_es is the Electron Spin Wavelength
from (21), -Lambda_R
is the Lorentz Factor from the proton's
perspective and +Lambda_R is the factor
from the electron's perspective both from
(8).
At n = 1
S_aH = -5.886981... x 10^-24 m^2
At n = 2
S_aH = -2.354792... x 10^-23 m^2
At n = 3
S_aH = -5.298283... x 10^-23 m^2
Which is interesting (at least to me) that
we have something as hard to get a handle
on as the Lorentz Factor tied in with
the basic geometry or a torus.
Interesting, but...
Now we will use the exact symbols used in
aerodynamics, but in this case on the much,
much smaller scale. This is the beginning
of the Mach-Cook Parallel. Let's begin
with the pressure exerted on the electron
simply for being in the Hydrogen atom. This
is analogous to that of the static air pressure
on an airplane without being in motion.

Where q is the Electron Charge
from (1) and S_aH
is the Hydrogen Surface Area from (103
& 104) from above.
At n = 1
P_s = +2.721558... x 10^4 C m^-2
At n = 2
P_s = -6.803896... x 10^3 C m^-2
At n = 3
P_s = +3.023954... x 10^3 C m^-2
Here we can begin to see once again the positive
to negative switching occuring, which we hadn't
see since equation (65).
This shows now that we are moving back toward
more electrodynamics in order to join
up with aerodynamics.
And just as the air pressure changes on an
airplane in motion, so too does the charge
pressure for the electron as it orbits.

Where rho_i is the Imaginary
Charge Density (resistance) from (40-42),
V_g is the Electron Group Velocity
(orbit velocity), V_gi is its Imaginary
counterpart from (6
& 7) and the Integers are negative
in accordance with the NET rule for
Integers.
At n = 1
q_c = -2.058918... x 10^23 C m^-2
At n = 2
q_c = +8.042650... x 10^20 C m^-2
At n = 3
q_c = -3.138117... x 10^19 C m^-2
It is here that Cook was able to link
up standard aerodynamics with the electron's
motion.
Where V_g is the Electron Group
Velocity (orbit velocity), V_gi is
its Imaginary counterpart from (6
& 7), the Integers are negative in
accordance with the NET rule for Integers,
c is the Velocity of Light,
ci its Imaginary counterpart, -Lambda_R
is the Lorentz Factor from the proton's
perspective, +Lambda_R is the factor
from the electron's perspective both from
(8), n is
the Quantum Number, Chi_R is
the Real Cook Factor from (19),
-alphai is the Imaginary Fine Structure
Constant pertaining to the proton and
+alphai pertaining to the electron
from (9 & 96).
At n = 1
c_p = 0.999946... (dimensionless)
At n = 2
c_p = 0.999986... (dimensionless)
At n = 3
c_p = 0.999994... (dimensionless)
Which eventually converges on one, as the
electron moves away from the proton. What
is infinitely more complicated to solve for
is the incompressible coefficient. Fortunately,
by looking at the denominator of (111) above,
we see a hint to the proof that will not be
shown here, as mentioned at the beginning
of this page.

Where c_p is the Pressure Coefficient
from (108-111) above, Z is the
Mach-Cook Number (represented as M
in aerodynamics), n is the Quantum
Number, -alphai is the Imaginary
Fine Structure Constant pertaining to
the proton, +alphai pertaining to the
electron from (9
& 96), Chi_R
is the Real Cook Factor from (19),
Lambda_R is the Lorentz Factor
from (8) and the
Integers are negative except the one in the
Sqruare Root in accordance with the rules
of the NET.
At n = 1
c_po = 0.999920... (dimensionless)
At n = 2
c_po = 0.999933... (dimensionless)
At n = 3
c_po = 0.999914... (dimensionless)
What's interesting in the above values, even
though they are almost equal to one, is that
whenever the electron is in even-numbered
orbitals, the Incompressible Coefficient
jumps up slightly. Look at the values
above again. Other than that, it converges
infinitely to zero as the electron moves further
and further from the proton.
Now, why is Z in there? And what is it?
We want to solve for it using (114). This
is the Mach Number in Aerodynamics
(you know the term, "Mach three,"
"Mach Five," etc.), but represented
as an M in those cases. In this case,
however, down at the atomic level, we will
call this the Mach-Cook Number Z,
which does not increase at exact Integers
like M. Fortunately, Jeff Cook
was able to discover exactly how it does
increase as the electron jumps from one orbital
to the next and has provided it for others
to work with.
Here it is...

Where alphai is the Fine Structure
Constant pertaining to the electron from
(9 & 96),
n is the Quantum Number, Re
(Xc (n)) is the Real part of the X-Wave
from (88 & 89)
and Im (Xc (n)) is the Imaginary part
from (90-93).
At n = 1
Zi = alphai (dimensionless)
At n = 2
Zi = 1.032001...i x 10^-2 (dimensionless)
At n = 3
Zi = 1.263938...i x 10^-2 (dimensionless)
I cannot begin to express how beautiful that
is!
Why?
Because this suggests not only that an electron
passes from orbital to orbital through the
joints of X-Waves, but also that an
airplane does the same when it travels >
speed of sound and that we too would be
able to seemlessly pass the so-called limit
of c without having an adverse effect
whatsoever.
It suggests that Einstein was mistaken
in his interpretation of his math that just
because the Lorentz Factor's values
become Imaginary once a mass in motion
approaches the speed of light, "the
speed of light therefore must be a
limiting velocity." This assessment seems
to not be true at all considering the
above equations.
To show that in greater detail, I will now
demonstrate the Lorentz Factor at the
speed of sound, which we can do based
on the equations above, as well as for the
speed of light with the same given
moving mass.
Being that the standard Mach number:
M = v / u, where v
is the velocity of the moving mass and u
is the speed of sound, referring to equation
(110) above, and that the standard Pressure
Coefficient: c_p = 1 - v^2
/ u^2, one can divide c_p (for
all velocities recorded of our moving
mass as it approaches and surpasses
u by minus one and then give its square
root in order to solve for the Lorentz
Factor in relation with the speed of
sound instead of the speed of light.
The dimensions will be the same, but the signs
will need some adjusting in accordance with
the New Electrogravuty Theory.
Now, if we record the values of the accelerating
mass at each fifty meters per second
faster in its travels, beginning with 100
meters per second, when the craft surpasses
u the Lorentz Factor becomes
Imaginary for all values thereafter. Here
are the values of this example on the Complex
Plane.
Surpassing u on the Complex
Plane
The first value on the Real axis closest
to zero is our first recorded value at 100
meters per second, and each to the right are
the next four. Then, just after breaching
u, our next value is 5.025189...i,
way up above our graph. Then the values descend
and converge on i.
Here are the values from our example if we
work from the speed of sound = 343 m s^-1:
At...
v = 100 m s^-2, Lambda_R = .304785...
v = 150 m s^-2, Lambda_R = .486283...
v = 200 m s^-2, Lambda_R = .717731...
v = 250 m s^-2, Lambda_R = 1.064562...
v = 300 m s^-2, Lambda_R = 1.804186...
v = 350 m s^-2, Lambda_R = 5.025189...i
v = 400 m s^-2, Lambda_R = 1.943695...i
Now, if we change the signs to be in-line
with the NET and then ignore the Imaginary
values, this is what the graph looks like...
Graph of surpassing u without
considering the Imaginary values

Why, it looks oddly like
that linear X-Wave in the image of
the logo at the top of this page!
Yup. That's why we're even discussing
this.
Now let's do the same thing
for this same mass passing c, breaching
the speed of light. Now consider, it
is this and only this (precisely) that
Einstein saw in his equations that led him
to conclude that nothing can travel faster
than c. And that's a solid fact.
Please again note that...this is
the exact same equation he used and what you
are about to see is exactly what he
saw that led him to that conclusion. There
is nothing else beyond this in his
entire theory that suggested or hinted
toward what you will see. Okay?
Let's record the values of the
speed of the mass at each 8 x 10^7 m s^-1,
beginning with the first record at 2 x 10^7
m s^-1, and use the Lorentz Factor
exactly as Einstein did, which is Lambda_R
= ( 1 - v^2 / c^2 )^-1.
Surpassing c on the Complex
Plane

In the same, the first mark
on the Real plane just to the right of zero,
actually to the right of one, is our first
recorded mark. Then as the mass approaches
c, the values move to the right on
the Real axis.
Once c is breached, in
accordance with Einstein's Theory of Relativity,
the values magically appear on the Imaginary
axis far north, descend and then converge.
The absolute only thing
different between this and the above example
with the speed of sound is that when
using the Lorentz Factor for the speed
of sound, the values begin at zero and
end at i. In the case with the speed
of light, the values begin at 1 and end
at 0. Mathematically, however, the exact
same distance on the Complex plane is transversed.
Isn't that a significant
difference though, that one begins and ends
at different values on the plane?
Not at all, in terms of a limiting
velocity! It means virtually nothing, as the
Lorentz Factor is a dimensionless property
and it's actual values have no real bearing
on the structure of the mass in travel anyway,
only its magnitude, which are identical. The
fact that there is no physical bearing of
Lorentz contraction on an actual traveling
mass was proven way back when, long before
Einstein's Relativity. And then in 1959 it
was proven by two physicists, one of which
is one of Cook's heroes (Roger Penrose),
who both proved in the same year that the
Lorentz Factor only has to do
with viewing angle, and many of Einstein's
conversations about his math could not exactly
be so. Again, nothing wrong with Einstein's
math, just some of his comments about it.
We are studying one of those here. However,
the fact that the values converge on a different
constant does suggest one very important thing
in terms of how an outside observer would
see things.
An outside observer listening
to a high speed jet pass the sound barrier
perpendicularly (from the observer) will no
longer hear the sound coming from from a straight
line point; rather, the sound seems to
follow from behind the jet. The sound remains
just as loud though as it did before the transition.
In fact, no matter how fast the jet travels
faster than u, the sound will not diminish
in the least; it will just follow farther
and farther behind it. This is because the
values converges on an Imaginary one. And
everyone knows that by multiplying a factor
of one by any dimension has no effect whatsoever.
This is not the case,
however, when multiplying a factor of zero
by any given dimension. In such case, the
dimension tends to cancel altogether. Thus,
in terms of the Lorentz Factor at play
with the speed of light, an outside
observer would begin to see the craft...well,
fade out.
And how fast would it fade
out?
It depends upon how fast the
craft is accelerating. If the plane
simply crosses c and then maintains
a steady superluminal velocity thereafter,
the craft might appear transluscent, a bit
faster: transparent--faster even more, invisible.
This is exactly what the math suggests by
it converging on zero instead of i.
Just remember, the Lorentz Factor has
no physical bearing on the craft itself from
its own point of view.
So again, if we change the signs in accordance
with the NET and ignore the i,
we can view these values linearly.
Graph of surpassing c without
considering the Imaginary values

Again the linear X-wave from
the logo at the top of this page?
That's right. Same very one.
Why do you think Mr. Cook studies this, 'cause
it's rewarding, 'cause chicks dig it? No.
'Cause he sees the connection. And that's
the only reason. It's there.
Okay, so what this says is
that we can test this experimentally, right?
Instead of using a radar gun to measure Length
Contraction, we can simply send sonar pulses
at a high-speed jet at multiple angles and
measure its contraction to verify this, right?
Yes and no. In 1959, Roger
Penrose also proved that Length Contraction
does not actually occur as Einstein's interpretation
suggested. Insetad, due to the viewing angle,
as a traveling mass approaches the
observer, the mass appears elongated,
as it passes, skewed and when
it travels away it appears contracted.
But yes, this would be a very straightforward
and important experiment to test.
Here's the setup for the Experiment
for Determining the Validity of the Mach-Cook
Parallel...
1) Acquire a small jet (easy
enough), capable of traveling almost up to
the speed of sound (could be a bigger challenge).
2) Record the actual length
of the jet before flight (of course).
3) Acquire 3 devices to send
sonar pulses through air.
4) Set up 3 flybys, one at 1/2
u, the second at 2/3 u and the
last up to (or slightly >) 90% u.
5) Angle the first (a) sonar
device facing the oncoming direction, one
(b) pointed straight up and the third (c)
angled in the outgoing direction...the devices
must be stationary of course.
6) During the flybys, using
sonar on multiply takes at high frequency,
record the length of the jet in flight.
EXPECTED RESULTS:
1/2 u: the jet should
appear slightly longer than it should be from
(a), slightly skewed from (b) and contracted
from (c)
2/3 u: the jet should
appear even more longer than it really is
from (a), even more skewed from (b) and even
more contracted from (c)
~90% u: the jet should
appear at its maximum elongation of the 3
speeds from (a), maximum skewed from (b) and
maximum contracted from (c)
What would all this prove?
Well, if it isn't obvious by
now, if the expected results occur exactly
as stated, it would 1) demonstrate that the
Mach-Cook Parallel is proven exactly
as Mr. Cook states, 2) Enstein
is absolutely 100% incorrect in stating that
nothing can travel faster than the speed of
light and 3) Roger Penrose is correct
about the Lorentz Factor and the viewing
angle.
Those are some heavy implications
hanging on a very replicable experiment...just
waiting to be tried!
If it doesn'tt occur exactly
as expected, then there are likely two other
possibilities (maybe more, but two that are
obvious). If the length is constant,
but indeed contracted at one
speed for (a), (b) and (c), then Roger
Penrose is incorrect about length
contraction, Einstein is
correct about it, but still wrong about surpassing
c and Cook is still right about
the Mach-Cook Parallel and being able
to surpass c.
The other obvious possibility
is that the length would turn out to be exactly
the same at all speeds, the same as its actual
length. This would mean Cook is completely
wrong about all this, Einstein is still
absolutely 100% correct about not being able
to surpass c, but probably still wrong
about length contraction and Penrose
is probably still completely correct and certainly
the awesome physicist his reputation provides
for him today.
But...which will it be?
In the meantime, until such
an experiment takes place, we shall now continue
with the NET, and the further implications
that follow in this theory.
Click
here to return to the Mach-Cook Parallel
Intro
Or continue or go back with the NET...
|